n^2+(2/3)n=-1/9

Solution for n^2+(2/3)n=-1/9 equation:

n^2+(2/3)n=-1/9

We move all terms to the left:

n^2+(2/3)n-(-1/9)=0


Domain of the equation: 3)n!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

n^2+(+2/3)n-(-1/9)=0

We multiply parentheses

n^2+2n^2-(-1/9)=0

We get rid of parentheses

n^2+2n^2+1/9=0

We multiply all the terms by the denominator


n^2*9+2n^2*9+1=0

Wy multiply elements

9n^2+18n^2+1=0

We add all the numbers together, and all the variables

27n^2+1=0

a = 27; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·27·1
Δ = -108
Delta is less than zero, so there is no solution for the equation